Physics, asked by Anonymous, 5 months ago

Question :-
If 784 J of work was done for lifting 20 kg mass, then calculate the height through which it was lifted.

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Answers

Answered by Anonymous
127

\underline{\red{ \bf {Solution}}} :-

 \underline {\green{\bf Given :-}}

  • Work Done(W) → 784 J
  • Mass (m) → 20 kg
  • Acceleration due to gravity (g) → 9.8 N

 \underline {\green{\bf To \: Find :-}}

  • Height (h)

 \underline {\purple{\bf Formula \: Used :-}}

  •  \underline{ \boxed {\blue{\sf{ W = m \times g \times h}}}}

Substituting Values

\sf \gray{\implies 784 = 20 \times 9.8 \times h}

\sf\gray{\implies 784 = 2 \cancel{0} \times  \dfrac{98}{ 1 \cancel{0} } \times h}

\sf\gray{\implies 784 = 2 \times 98h}

\sf\gray{\implies 784 = 169h}

\sf\gray{\implies h =  \dfrac{784}{196}}

\bf\gray{\implies h = 4}

Thus, the height is 4 m

Hence, Solved

Answered by Anonymous
98

Answer

Given :-

  • Work done, W = 784 J
  • Mass of body, m = 20 kg
  • Acceleration due to gravity, g = 9.8 m/s²

To find :-

Height through which it was lifted - h

Solution

We know, W = mgh

  • W = 784
  • m = 20 kg
  • g = 9.8 m/s²

Substituting the value in formula :-

\sf W = mgh

\sf 784 = 20 \times 9.8 \times h

\sf 784 = 196h

\sf h = \frac{784}{196}

\sf h = 4 m

Height through which it was lifted is 4m

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