Question
If ∠A and ∠B are acute angles such that cos A = cos B, then show that ∠A = ∠B.
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cos A=cos B
therefore by comparison;
A=B
Hence proved.
This method can't be used in two different triangles.
therefore by comparison;
A=B
Hence proved.
This method can't be used in two different triangles.
Answered by
1
HEY THERE!!
Question;
If ∠A and ∠B are acute angles such that cos A = cos B, then show that ∠A = ∠B.
Method of Solution;
Let us consider right angled triangle ACB.
We know that Cos A = Adjacent Side/Hypotenuse
Thus, In right Angled triangle ∆ ACB
We have COS A = AC/AB
We have COS B = BC/AB
•°• Cos A = Cos B
°•° AC = BC
By Using Opposite side is Equal to the Opposite Angle!!
•°• ∠A = ∠B
PROVED!!!
Question;
If ∠A and ∠B are acute angles such that cos A = cos B, then show that ∠A = ∠B.
Method of Solution;
Let us consider right angled triangle ACB.
We know that Cos A = Adjacent Side/Hypotenuse
Thus, In right Angled triangle ∆ ACB
We have COS A = AC/AB
We have COS B = BC/AB
•°• Cos A = Cos B
°•° AC = BC
By Using Opposite side is Equal to the Opposite Angle!!
•°• ∠A = ∠B
PROVED!!!
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