Question
If ∠A and ∠B are acute angles such that cos A = cos B, then show that ∠A = ∠B.
class 10 maths chapter 8
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Heya mate , Here is ur answer
Given:Cos A = Cos B
To prove : <A=<B
Proof:Cos A=Cos B
![\frac{base}{hypo} = \frac{base}{hypo} \frac{base}{hypo} = \frac{base}{hypo}](https://tex.z-dn.net/?f=+%5Cfrac%7Bbase%7D%7Bhypo%7D++%3D++%5Cfrac%7Bbase%7D%7Bhypo%7D+)
Base for cos A=AC
Base for Cos B=BC
Hypo=AB
![\frac{ac}{ab} = \frac{bc}{ab} \frac{ac}{ab} = \frac{bc}{ab}](https://tex.z-dn.net/?f=+%5Cfrac%7Bac%7D%7Bab%7D++%3D++%5Cfrac%7Bbc%7D%7Bab%7D+)
AC=BC
<B=<A(angles opposite to equal sides are equal)
Warm regards
@Laughterqueen
◦•●◉✿[Tʜᴀɴᴋ ʏᴏᴜ]✿◉●•◦
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Given:Cos A = Cos B
To prove : <A=<B
Proof:Cos A=Cos B
Base for cos A=AC
Base for Cos B=BC
Hypo=AB
AC=BC
<B=<A(angles opposite to equal sides are equal)
Warm regards
@Laughterqueen
◦•●◉✿[Tʜᴀɴᴋ ʏᴏᴜ]✿◉●•◦
Be Brainly✌✌
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