Math, asked by aleenarkawde, 4 months ago


Question : If a²+ b² + c²= ab + bc + ac, then the value of a+c/b is
1. 6
2. 2
3. 1
4. - 1​

Answers

Answered by thakursamar432
0

Step-by-step explanation:

a

3

+ b

3

+ c

3

- 3abc

= (a

2

+ b

2

+ c

2

- ab - bc - ca)(a + b + c)

= a

2

+ b

2

+ c

2

= ab + bc + ca (given)

⇒ (a

2

+ b

2

+ c

2

- ab - bc - ca) = 0

∴ a

3

+ b

3

+ c

3

- 3abc

(a + b + c) x 0 = 0

∴ a

3

+ b

3

+ c

3

= 3abc

Answered by yashaswini495
0

Answer:

2

Step-by-step explanation:

We know that sum of perfect squares is greater than or equal to zero

So,

(a−b)²+(b−c)²+(c−a)²>=0

So , expanding this we get,

a²+b²+c²>=ab+bc+ac

But in the question the reverse inequality is given

a²+b²+c² < =ab+bc+ac

Hence it follows that ,

a²+b²+c²=ab+bc+ac

So ,

(a−b)²+(b−c)²+(c−a)²=0

Hence,

a=b=c

So a+bc=2

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