Question

question ) . if α , β are roots of ax²+bx+c=0 then find
1) α+β
2) α.β
3) 1\α+1/β
4) α²+β²
5) (α–β)²
6) α–β​

Answer 1

Answer:

1) α+β= -b/a

2) α.β= c/a

3) 1\α+1/β= statement is no clear

4) α²+β²=(α+β)²-2α.β=b²/a²-2c/a= (b²-2ac)/a²

5) (α–β)²=(α+β)²-4α.β=b²/a²-4c/a= (b²-4ac)/a²

6) α–β=√{(b²-4ac)/a²}=√b²-4ac/a....

Answer 2

Here is the answer.

See the answer