Question

Question :

if f(x)=√2cosx-1 /cotx-1 ; x ≠ π/4
to find the value of f(π/4).
so that f(x) becomes continuous at x = π/4 .​

Answer :

f(π/4)= -1/2

Step by step exaplaination :

=>Here,
f(x)
=√2cosx-1 /cotx-1
=√2cosx-1 /(cosx /sinx)-1
=(√2cosx-1)(sinx) /cosx-sinx

=>Using L' hospital rule :
lim_(x→c) [f(x) /g(x)] = lim_(x→c) [f(x') /g(x')]

=>Now,
lim_(x→c) [f(x) /g(x)]
= lim_(x→c) [√2sinx /(-cosec²x)]

=>We get,
f(π/4)
= √2sin(π/4) /(-cosec²(π/4))
= √2(1/√2) /(-(√2)²)
= 1 /(-2)
= -1/2


" Nothing is impossible "
" Everyone's knowledge is not the same please change your things. "


​

Answer 1

Step-by-step explanation:

Answer :

f(π/4)= -1/2

Step by step exaplaination :

=>Here,

f(x)

=√2cosx-1 /cotx-1

=√2cosx-1 /(cosx /sinx)-1

=(√2cosx-1)(sinx) /cosx-sinx

=>Using L' hospital rule :

lim_(x→c) [f(x) /g(x)] = lim_(x→c) [f(x') /g(x')]

=>Now,

lim_(x→c) [f(x) /g(x)]

= lim_(x→c) [√2sinx /(-cosec²x)]

=>We get,

f(π/4)

= √2sin(π/4) /(-cosec²(π/4))

= √2(1/√2) /(-(√2)²)

= 1 /(-2)

= -1/2

" Nothing is impossible "

" Everyone's knowledge is not the same please change your things. "

Answer 2

Answer:

ddh-kqaj-vqc all age girlssss aa jao grmi sant kr dunga

all age gir.l come for late night fun with me ❤️❤️