Question

Question:-​

If p,q are the roots of ax² - bx + c = 0 ( a ≠ 0 ), then p + q is

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Answer 1

Answer:

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Answer 2

Step-by-step explanation:

x = (-b ± √(b2 - 4ac)) / 2a

where a, b, and c are coefficients.

In this,

a = a

b = -b

c = c

The plus/minus sign indicates that we will have two solutions. Suppose that root p was found using the plus and root q was found using the minus. We will have these roots.

p = (b + √(b2 - 4ac)) / 2a and

q = (b - √(b2 - 4ac)) / 2a

Since we want to find the value of p + q, we simply add the formula.

p + q = ((b + √(b2 - 4ac)) + (b - √(b2 - 4ac))) / 2a

The square-root terms cancel each other out.

p + q = 2b / 2a

p + q = b / a