Question

Question

If
$x \: = (3 + \sqrt{8)}$
Then find the value of
$( {x}^{2} + \frac{1}{x} {}^{2}$




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$target = 350$
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Answer 1

Answer:

x = 3+ √8

x = (3+√8)(3-√8) / (3-√8)

x = (9 -8) / (3-√8)

x = 1/ (3 -√8)

Or we can write 1/x = (3-√8)

Put the value and find out

x² +(1/x²) = x² + (1/x)²

So x² + 1/ x² = (3 +√8)² + (3 -√8)²

= 9+6√8+8 + 9–6√8+8

= 34. Ans.

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Answer 2

in which std do you study