Math, asked by Anonymous, 3 days ago

Question!

If the length of rectangle is thrice of its breadth and it's perimeter is 32 cm then finds its area​.

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Answers

Answered by LEGENDARYCONQUEROR
0

Answer:

WE KNOW THAT PEMIETER IS 32

LENGTH AND BREADTH WILL COMBINE AND MAKE UP TO = 16

LENGTH = 12 BREADTH = 4

12 × 4 = ANSWER

= 48

YOUR ANSWER IS 48

Answered by BrainlyPrivacy
46

Given :-

  • Length of Rectangle is thrice of it's breadth.
  • Perimeter of Rectangle = 32 cm.

To Find :-

  • Area of Rectangle ?

Solution :-

  • Let the breadth of rectangle be y.
  • As it is stated that length of rectangle is thrice of its breadth so length of rectangle will be 3y.

Using formula,

  • Perimeter of rectangle = 2(l + b)

Where,

  • l denotes length of rectangle
  • b denotes breadth of rectangle

We have,

  • Length of rectangle (l) = 3y
  • Breadth of rectangle (b) = y
  • Perimeter of rectangle = 32 cm

• Putting all values in formula,

➻ 32 = 2(3y + y)

➻ 32 = 2(4y)

➻ 32 = 2 × 4y

➻ 32 = 8y

➻ 8y = 32

➻ y = 32/8

y = 4

Using formula,

  • Area of rectangle = l × b

Where,

  • l denotes length of rectangle
  • b denotes breadth of rectangle

We have,

  • Length of rectangle (l) = 3y
  • Breadth of rectangle (b) = y

• Putting all values in formula,

➻ Area of rectangle = 3y × y

➻ Area of rectangle = 3 × y × y

➻ Area of rectangle = 3 × y²

• Putting values of y,

➻ Area of rectangle = 3 × 4²

➻ Area of rectangle = 3 × 4 × 4

➻ Area of rectangle = 12 × 4

Area of rectangle = 48 cm²

  • Hence, area of rectangle is 48 cm².

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