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If the length of rectangle is thrice of its breadth and it's perimeter is 32 cm then finds its area.
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Answer:
WE KNOW THAT PEMIETER IS 32
LENGTH AND BREADTH WILL COMBINE AND MAKE UP TO = 16
LENGTH = 12 BREADTH = 4
12 × 4 = ANSWER
= 48
YOUR ANSWER IS 48
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Given :-
- Length of Rectangle is thrice of it's breadth.
- Perimeter of Rectangle = 32 cm.
To Find :-
- Area of Rectangle ?
Solution :-
- Let the breadth of rectangle be y.
- As it is stated that length of rectangle is thrice of its breadth so length of rectangle will be 3y.
Using formula,
- Perimeter of rectangle = 2(l + b)
Where,
- l denotes length of rectangle
- b denotes breadth of rectangle
We have,
- Length of rectangle (l) = 3y
- Breadth of rectangle (b) = y
- Perimeter of rectangle = 32 cm
• Putting all values in formula,
➻ 32 = 2(3y + y)
➻ 32 = 2(4y)
➻ 32 = 2 × 4y
➻ 32 = 8y
➻ 8y = 32
➻ y = 32/8
➻ y = 4
Using formula,
- Area of rectangle = l × b
Where,
- l denotes length of rectangle
- b denotes breadth of rectangle
We have,
- Length of rectangle (l) = 3y
- Breadth of rectangle (b) = y
• Putting all values in formula,
➻ Area of rectangle = 3y × y
➻ Area of rectangle = 3 × y × y
➻ Area of rectangle = 3 × y²
• Putting values of y,
➻ Area of rectangle = 3 × 4²
➻ Area of rectangle = 3 × 4 × 4
➻ Area of rectangle = 12 × 4
➻ Area of rectangle = 48 cm²
- Hence, area of rectangle is 48 cm².
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