Question

Question :
_________

If the sum of the zeroes of the polynomial p(x) = (k2 – 14) x2 – 2x – 12 is 1,
➡️ then find the value of k ?


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Answer 1

Answer:

sum of zeroes - -b/a

1 = 2/k2-14

k2 - 14 = 2

k2 = 16

k = 4

Answer 2

Answer:

The given polynomial is (k²-14)x²-2x-12

The sum of zeros of a quadratic equation is -b/a.

Hence, the sum of the zeros of the given quadratic is

-(-2)/(k²-14)

2/(k²-14)

Now, from the given directions, this expression should be equal to 1.

2/(k²-14) = 1

k²-14 = 2

k² = 16

k = ñ4

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