✯ Question :-
If the sum of two positive square are 765. Also, the first square is greater than other by 3. Then find the number
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Answered by
158
- The sum of the 2 positive square is 765. The square of the 1st number is greater than the other number by 3.
- The numbers
- The sum of the 2 positive square numbers is 765.
First,
- Let the 1st number be x and 2nd number be y.
According to the question,
- x² + y² = 765
Second,
- The square of 1st number is greater than the other by 3.
This implies that,
- x = y + 3
- x² = (y + 3)²
- x² = y² + 9 + 6y
Substituting x² = y² + 9 + 6y in x² + y² = 765,
- x² + y² = 765
- y² + 9 + 6y + y² = 765
- 2y² + 6y + 9 = 765
- 2y² + 6y = 765 - 9
- 2y² + 6y = 756
- 2y² + 6y - 756 = 0
- 2 (y² + 3y - 378) = 0
- y² + 3y - 378 = 0
Using PSF method,
- P = - 378 * y² = - 378y²
- S = + 3y
- F = + 21 y , - 18 y
Now,
- y² + 21y - 18y - 378 = 0
- y (y + 21) - 18 (y + 21) = 0
- (y + 21) (y - 18) = 0
- y + 21 = 0 , y - 18 = 0
- y = - 21 , y = + 18
Since, numbers cannot be negative.
- y = 18
Now,
- x = y + 3
- x = 18 + 3
- x = 21
Therefore,
- x² + y² = 765
- 21² + 18² = 765
- 441 + 324 = 765
- 765 = 765
LHS = RHS
Hence, verified.
Answered by
44
Question :
If the sum of two positive square are 765. Also, the first square is greater than other by 3. Then find the number
Solution :
Let the numbers be x and y.
Now x + y = 765 …(1)
x - y = 3 …(2). Add (1) and (2) to get
2x = 768, or
x = 384, so y = 765 - 384 = 381.
The difference of the their squares is (384+381)(384-381) = 765 × 3 = 2,295.
Check: The difference of their squares
= 384^2 - 381^2 = 147,456 - 145,161
= 2,295
The difference of the squares of the two numbers is = 765.
Answer :
The difference of the squares of the two numbers is = 765.
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