Question: If x = (-23)+(22)+(-23)+(22)+.. .. .. 40 terms And y= (11)+(-10)+(11)+(-10)+.. .. .. 20 terms then find y-x
Answers
x = (-23)+(22)+(-23)+(22)+.. .. .. .. 40 terms
Y = (11)+(-10)+(11)+(-10).. .. .. .. 20 terms
x = 20 pairs of (-23)+(22)= -1
There are 20 pairs so we will get - 1 [20 times]
So, x = - 1×20= -20
Y = 10 pairs of (11)+(-10) = 1
There are 10 pairs so we will get 1[10 times]
So, Y = 1 × 10 = 10
We have to find the value of:-
y - x = 10 - (-20)
= 10 + 20
= 30
Step-by-step explanation:
x = (-23)+(22)+(-23)+(22)+.. .. .. .. 40 terms
Y = (11)+(-10)+(11)+(-10).. .. .. .. 20 terms
x = 20 pairs of (-23)+(22)= -1
There are 20 pairs so we will get - 1 [20 times]
So, x = - 1×20= -20
Y = 10 pairs of (11)+(-10) = 1
There are 10 pairs so we will get 1[10 times]
So, Y = 1 × 10 = 10
We have to find the value of:-
y - x = 10 - (-20)
= 10 + 20
= 30