Question

question:- If y=log(sinx), find
dx
dy




Given that y=log(sinx), we need to find the value of
dx
dy
​

We know that the derivative of log(x) w.r.t x is
x
1
​

⟹
dx
dy
​
=
dx
d
​
(log(sinx))=
sinx
1
​
×
dx
d
​
(sinx)=
sinx
1
​
×cosx=cotx
Hence,
dx
dy
​
=cotx​

Answer 1

Answer:

cost 4 is the answer for question