Question

question ii prove with solution

Answer 1

tan^2thita can be written as sec^2-1
sec2-1 upon (sec-1)^2

(sec-1)(sec+1) (a+b)(a-b)=a^2 -1
(sec-1)(sec-1)


sec+1
sec-1


convert sec to 1 upon cos take cos as lcm the denominator will be canceled remaing 1+cos upon 1-cos

Answer 2

hope this hlp.......