Question

question iii) prove it with solution

Answer 1

We know that (a+b)^2 = a^2+b^2+2ab.

                        (a - b)^2 = a^2+b^2-2ab.


Given LHS = (1 + tanA)^2 + (1 - tanA)^2.

                   = 1 + tan^2A + 2tanA + 1 + tan^2A - 2tanA

                   = 2 + 2tan^2A

                   = 2(1 + tan^2A)

                   = 2(sec^2A)

                   = 2 sec^2A.


LHS = RHS.


Hope this helps!

Answer 2

Hey mate..
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The answer is in the attachment

Hope it helps ™