Question

Question in a photo give me all answer​

Answer 1

Answer:

1.

i) 5^(4-3)

=5^1

=5

ii) 7^(5-3)

=7^2

=49

iii) 11^(5-3)

=11^2

=121

2.

i) 3^2×2^2

=(3×2)^2

=6^2

=36

ii) 5^(2+3)

=5^5

=3125

iii) 7^(3+1)

=7^4

=2401

3.

i) 2^(2×2)

=2^4

=16

ii) 13^(2×1)

=13^2

=169

iii) 3^(2×3)

=3^6

4.

i) (2/7)^3

ii) (3/5)^4

iii) (5/7)^2

5.

i) 1/11^2

=1/121

ii) 3^-3

=1/3^3

=1/27.

HOPE THIS BRING A SMILE IN YOUR FACE AND

Step-by-step explanation:

Answer 2

SOLVING EXPONENTS

1. Evaluate:

$Identity \ used \ :-\\\\\frac{a^{m} }{a^{n} } = a^{m-n}$

$i) \ \frac{5^{4} }{5^{3} }\\\\ = 5^{4-3} \\\\ = 5\\\\\\ii) \ \frac{7^{5} }{7^{3} }\\\\ = 7^{5-3}\\\\ = 7^{2}\\\\ = 49\\\\\\iii)\ \frac{11^{5} }{11^{3} }\\\\ = 11^{2}\\\\ = 121$

2. Evaluate:

$Identity \ Used \ :-\\\\ a^{m} * b^{m} = (ab)^{m}\\\\\\i) \ 3^{2} * 2^{2}\\\\ = 6^{2} \\\\ = 36\\ \\\\ Identity \ Used \ :-\\\\ a^{m} * a^{n} = a^{m+n}\\\\\\ ii) \ 5^{2} * 5^{3} \\\\ = 5^{3+2} \\\\ = 5^{5} \\\\ = 3125\\\\\\iii) \ 7^{3} * 7^{1}\\\\ = 7^{3+1} \\\\ = 7^{4}\\\\ = 2401$

3. Evaluate:

$Identity \ Used \ :- \\\\(a^{m})^{n} = a^{mn} \\\\\\i) \ (2^{2})^2 \\\\ = 2^{2 * 2}\\\\ = 2^{4}\\\\ = 16\\\\\\ii) \ (13^{2})^1\\\\ = 13^{2 * 1}\\\\ = 13^{2}\\\\ = 169\\\\\\iii) \ (3^{2})^3\\\\ = 3^{2 * 3}\\\\ = 3^{6}\\\\ = 729$

4. Evaluate:

$Identity \ Used \ :-\\\\\frac{a^{m}}{b^{m}} = (\frac{a}{b})^{m}\\\\\\i) \ \frac{2^{3}}{7^{3}} = (\frac{2}{7})^{3}\\\\ii) \ \frac{3^{4}}{5^{4}} = (\frac{3}{5})^{4}\\\\iii) \ \frac{5^{2}}{7^{2}} = (\frac{5}{7})^2$

5. Evaluate:

$Identity \ Used \ :-\\\\a^{-m} = \frac{1}{a^{m}} \\\\\\i) \ 11^{-2} = \frac{1}{11^{2}} = \frac{1}{121} \\\\ii) \ 3^{-3} = \frac{1}{3^{3}} = \frac{1}{27}$

NOTE :- Whenever the answer comes in high exponents, you can leave the answer in the exponential form only.