Math, asked by rashmitamishtiroy, 3 months ago

Question:-In a three-digit number,the unit's digit is thrice the hundred's digit.Also,the ten's digit is obtained by adding the hundred's digit and the unit's digit. If the sum of the digits of the no.is 16,then find the original number.
Pls answer this pls ​

Answers

Answered by cαlypso
41

Given

  • 3 digit number.
  • Unit's digit is thrice the hundred's digit.
  • Ten's digit is obtained by adding hundred's digit and the unit's digit.
  • Sum of digits of the number is 16.

_______________________________

To Find

  • The original number.

_______________________________

Solution

Let the hundred's digit be 'x'.

One's digit ⇒ 3x

Ten's digit is obtained by adding hundred's digit and the unit's digit.

x + 3x = 4x

Ten's digit ⇒ 4x

After adding the digits we get 16. So we will solve this equation to find the original number ⇒ x + 4x + 3x = 16

Let's solve your equation step-by-step.

x + 4x + 3x = 16

Step 1: Simplify the equation.

⇒ x + 4x + 3x = 16

⇒ 8x = 16

Step 2: Divide 8 from both sides of the equation.

⇒ 8x ÷ 8 = 16 ÷ 8

⇒ x = 2

∴ x = 2

∴ One's digit ⇒ 3x ⇒ 3(2) ⇒ 6

∴ Ten's digit ⇒ 4x ⇒ 4(2) ⇒ 8

∴ Hundred's digit ⇒ x ⇒ 2

∴ The original number is 286

_______________________________


Anonymous: Fantastic :D
cαlypso: Thanks ❤
Anonymous: perfect :p
cαlypso: Thanks ❤
Anonymous: :)
Answered by Anonymous
30

Question :-

→ In a three-digit number ,the unit's digit is thrice the hundred's digit. Also ,the ten's digit is obtained by adding the hundred's digit and the unit's digit. If the sum of the digits of the no.is 16,then find the original number.

Given :-

→ The original no. is a 3 digit number

→ Unit's digit is thrice the hundred's digit

→ Ten's digit is obtained by adding the hundred's digit and the unit's digit

→ Sum of all digits of the original number is 16

To Find :-

→ The original number

Solution :-

→ Let the hundred's digit be ' x '

  then, the unit's digit will be  ' 3x '

 and , the ten's digit will be ' 3x + x \; = \; 4x '

→ As we're given that sum of all digits is 16

  then we can write original no. as ,

 \longrightarrow x + 3x + 4x = 16

→ Let's solve the equation !

\longrightarrow x + 3x + 4x = 16\\\\\longrightarrow 8x = 16 \\\\\longrightarrow x  = \dfrac{16}{8} \\\\\longrightarrow x = 2

∴ Unit digit ⇒ 3x ⇒ 3 × 2 ⇒ 6

∴ Ten's digit ⇒ 4x ⇒ 4 × 2 ⇒ 8

∴ Hundred's digit ⇒ x ⇒ 2

{\huge{\rm{\underline{\underline{Original \: Number \: = \: 286}}}}}

All Done ! :D

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