Question

Question :-

In an isosceles triangle ABC, if
AB = AC = 35 and BC = 20 then the measure of altitude from A on BC is?​

Answer 1

Answer:

ABC is iscocelus triangle

If BC is Base of triangle then other 2 sides will equal

So

AC=AB

Make altitude AD

By using pythagoras

AD will half BC

BC will 10cm

AD=root (35^2 - 10^2)

AD root 1125

Answer 2

⛦Correct Question :-

• In an isosceles triangle ABC, if AB = AC = 35 and BC = 20 then the measure of altitude from A on BC is?

$\huge{\blue{\bold{\underline{\underline{Answer :}}}}}$

⛦Given:-

• ∆ABC is an isosceles triangle
• AB = AC = 35 unit
• Bc= 20 unit

⛦To find:-

• side AD

⛦Solution:-

In ∆ABD and∆ADB

<ADB= <ABD_______[each angle 90°]

AB = AC_________[given each angle 35°]

AD = AD_________[common]

then

∆ABD ≅ ∆ADB _____[by R-H-S criteria]

by cpct:-

BD= CD=10 unit

Now,in ∆ADB

By Pythagoras theorm__

⟼AD²+BD²=AB²

⟼AD²+10²=35²

⟼AD²=(35)²-10)²

⟼AD²=1225-100

⟼AD²=1125q

⟼AD=√1125

⟼AD≈ 33.5

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