Question

Question in attachement. If answer will bwe wright then brainliest.

Answer 1

Given a + b + c = 5 and ab + bc + ca = 10.

We know that a^3 + b^3 + c^3 - 3abc = (a + b + c)(a^2 + b^2 + c^2 - ab - bc - ca) --(1)

We know that (a + b + c)^2 = a^2 + b^2 + c^2 + 2ab + 2bc + 2ca

= > (5)^2 = a^2 + b^2 + c^2 + 2(ab + bc + ca)

= > 25 = a^2 + b^2+ c^2 + 2(10)

= > 25 = a^2 + b^2 + c^2 + 20

= > a^2 + b^2 + c^2 = 5  ------ (2)


Substitute (2) in (1), we get

= > a^3 + b^3 + c^3 - 3abc = (5)(5 - 10)

                                            = 5(-5)

                                            = -25.


Therefore a^3 + b^3 + c^3 - 3abc = -25.


Hope this helps!

Answer 2

Hi,

Please see the attached file!


Thanks