Physics, asked by nivedita3028, 9 months ago

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Answered by Anonymous
1

\huge{\underline{\underline{\bf{Answer:-}}}}

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Electric flux and Gauss law:

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The electric flux is defined as the dot product of the electric field and the area vector.

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  • According to Gauss law, the electric flux is given as follows:

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 ϕ= \frac{Q}{ϵo}

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Where,

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  • Q is the charge enclosed in the gaussian surface.

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  • ϵo is the electric permittivity of the free space.

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{\purple{\underline{\underline{\mathsf{\pink{Answer\:and\:Explanation:}}}}}}

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Given Data:

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charge \: 1,(q1) = 3.4 \: nC

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charge \: 2,(q2) =  - 6.00 \: nC

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(A)

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Now, the charge 2 will be inside the sphere of the radius ( {r}^{2} ) = 1.55 \: m,therefore the enclosed charge would be

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Q =  q_{2}

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Q =  - 6 \: nC

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Therefore, the electric flux would be

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 ϕ= \frac{Q}{ϵo}

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 =  \frac{ - 6 \times 10 {}^{ - 2}C }{8.8 \times 10 {}^{ - 12} }

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 =  - 678 \: N {m}^{2} C

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(B)

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In this sphere both charge will be inside the sphere.

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Q =  q_{1}  + q_{2}

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Q =  3.4 - 6

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Q =   - 2.6nC

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Therefore, the electric flux would be

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 ϕ= \frac{Q}{ϵo}

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 =  \frac{ - 2.6 \times 10 {}^{ - 2}C }{8.5 \: \times 10 {}^{ - 12} }

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 =  - 263 \: Nm {}^{2} C

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Answered by msatvik355
0

Answer:

The answer is

Electric flux and Gauss law.

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