Question

нσℓα♥

QUESTION IN ATTACHMENT​

Answer 1

Answer:

option A

Step-by-step explanation:

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Answer 2

Step-by-step explanation:

$f(x) = y =\frac{e^x}{logx}$

$f'(x) = y' =\frac{logx*e^x - \frac{e^x}{x}}{(logx)²}$

$f'(x) =\frac{e^x(logx - \frac{1}{x})}{(logx)²}$

$f'(x)=\frac{e^x(xlogx - 1)}{x(logx)²}$