Question

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Answer 1

Answer:

According to the law of floatation

weight of the block=weight of the two liquids displaced 

LADg=4LA(2d)g+43LAdg⇒D=21d+43d=45d

Answer 2

Explanation:

Weight of the solid body = Thrust exerted by $\tt 1^{\text {st }}$ liquid + Thrust exerted by $\tt 2^{\text {nd }}$ liquid

$\[ \begin{array}{l} \tt m g=F_{B_{1}}+F_{B_{2}} \\ \\ \displaystyle \tt \Rightarrow \quad D \times L \times \frac{A}{5} \times g=d \times \frac{3 L}{4} \times \frac{A}{5} \times g+2 d \times \frac{L}{4} \times \frac{A}{5} \times g \\ \\ \displaystyle \tt \Rightarrow \quad D=\frac{3 d}{4}+\frac{2 d}{4} \\ \\ \displaystyle \tt \Rightarrow \quad D=\frac{5 d}{4} \end{array} \]$

Therefore, correct option is (D).