Question

QUESTION in attachment
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Answer 1

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Given:

OP,OQ,OR, and OS are four rays.

Theory:

Circle possesses over ray is 360°

Solution:-

∠POQ + ∠QOR + ∠SOR + ∠POS

Forms out a complete circle on the rays OP, OQ, OR and OS

Taking ray OQ

Its forms out a complete circle.

Hence,

⇒ ∠POQ + ∠QOR + ∠SOR + ∠POS = 360°

Answer 2

Answer with

Step-by-step explanation:

there are many ways to prove this ans and this is one of the simplest ways to do so.......

statement:∠POQ+∠QOR+∠SOR+POS=360°

RTP:total angle O is 360°

proof:draw a circle connecting points P,Q,R,S with O as centre..

obviously in a circle,angle at the centre is 360°

so tot. ∠O must be 360° to satisfy this rule.............

hence proved..................

hope it helps............pls mark my ans the brainliest if u have a sec.........tq.....