Question

question - In Fig. 6.40, E is a point on side CB produced of an isosceles triangle ABC
with AB = AC. If AD ⊥ BC and EF ⊥ AC,
prove that Δ ABD ~ Δ ECF.

calss 10th maths chapter triangle
6.3 question no. 11 ❣❣❣❣❣❣❣❣❣
❣❣✧༺♥༻✧✧༺♥༻✧❣❣
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Answer 1

Answer:

In∆ABD and∆ECF

angleD=angleF=90

InABC

angleB=angleC ( it is isocelus triangle)

angleC= angleC( angleB= angleC)

∆ABD~∆ECF

Answer 2

Hey Aditya hii.

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