Question

question: in fig, prove that :
(i) AR is parallel to BC
(ii) CM=AL​

Answer 1

Answer:

Given: two ∆s, ∆BCL and ∆RMA, BL = RM, BC = RA.

To prove: AR ll BC and CM = AL.

Proof: In ∆BCL and ∆RMA

angle L = angle M (each 90°)

BL = RM

RA = BC

=>∆BCL ≅ ∆RMA. ( RHS )

=>angle C = angle A. (CPCT)

but these are alternate interior angles

=>AR ll BC

now, CL = MA. (CPCT)

=> CM + ML = ML + LA

=> CM = AL

HENCE PROVED....