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1
Answer:
Let AC be a ladder, AB is the wall and BC is the ground as shown in the figure.
We know that
cos60
o
=
AC
BC
2
1
=
AC
2.5
AC=5 m
Therefore, the length of ladder is 5 m.
plzz mark brainliest
Answered by
1
Answer:
Step-by-step explanation:
tan theta = p/b
p here is hieght the ladder.
tan 60 = p/10
(3^1/2)/2 = p/10
5*3^1/2 = p
height of the ladder is 5 root 3 meters.
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