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Answered by spacelover123
41

Question

\sqrt[3]{333+\sqrt[3]{987+\sqrt[3]{2197} } } is equal to

(a) 21

(b) 18

(c) 7

(d) 3

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Answer

\sqrt[3]{333+\sqrt[3]{987+\sqrt[3]{2197} } }

To solve this, we must find the cube roots of the required number. Let's find the cube root of 2197 first.

First, we'll Prime factorize 2197

\begin{array}{r | l}   13 & 2197 \\ \cline{2-2}  13 & 169   \\ \cline{2-2}  & 13  \\  \end{array}

2197 = 13 × 13 × 13

2197 = (13 × 13 × 13)

∛2197 = 13

∴ ∛2197 is 13.

Since we found the cube root of 2197, we'll replace it with the expression we are solving and simplify it.

\sqrt[3]{333+\sqrt[3]{987+13 } }

\sqrt[3]{333+\sqrt[3]{1000 } }

Now we'll find the cube root 1000.

We'll Prime factorize 1000 first to find the cube root.

\begin{array}{r | l}   2 & 1000 \\ \cline{2-2}  2 & 500  \\ \cline{2-2} 2 & 250  \\ \cline{2-2} 5 & 125 \\ \cline{2-2} 5 & 25 \\ \cline{2-2} & 5\\     \end{array}

1000 = 2 × 2 × 2 × 5 × 5 × 5

1000 = (2 × 2 × 2) × (5 × 5 × 5)

∛1000 = 2 × 5

∛1000 = 10

∴ ∛1000 is 10.

Since we found the cube root of 1000, we'll replace it with the expression we are solving and simplify it.

\sqrt[3]{333+\sqrt[3]{1000 } }

\sqrt[3]{333+10 }

\sqrt[3]{343}

Now we have to find the cube root of 343 in order to complete the simplification of the expression.

First, we'll Prime Factorize 343.

\begin{array}{r | l}   7 & 343 \\ \cline{2-2}  7 & 49   \\ \cline{2-2}  & 7 \\  \end{array}

343 = 7 × 7 × 7

343 = (7 × 7 × 7)

∛343 = 7

∴ ∛343 is 7.

Since we found the cube root of 343, we'll replace it with the expression we are solving and simplify it.

\sqrt[3]{343}

7

\bf \therefore \sqrt[3]{333+\sqrt[3]{987+\sqrt[3]{2197} } } = 7}

∴ The answer is (c) 7.

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Answered by Anonymous
34

{\blue{  \sqrt[3]{333} +  \sqrt[3]{987} +  \sqrt[3]{2197}} =\purple{ \sqrt[3]{333 +  \sqrt[3]{987 + 13} }}} \\  \\ \green{ \sqrt[3]{333 +  \sqrt[3]{1000} }}  =\red{ \sqrt[3]{333 + 10}} \\  \\  \orange{ \sqrt[3]{343}  = 7} \\  \\  \\

So option C is correct

\red{REFER  \:  \: THE  \:  \: ATTACHMENT}

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