Question

Question in the attachment... (above)​

Answer 1

Money he borrows = 8000

Interest he will pay = 1360

Total money he will pay after = 8000 + 1360 = 9360

Now he will pay in 12 installments with a difference of 40 in each installment.

This is a form of AP,

where common difference d = -40, number of terms n = 12, and sum of 12 terms is 9360

So,

Sum of n terms in AP is

Sum = n/2 [ 2a + (n - 1)d ]

9360 = 12/2 [ 2a - 40(12 - 1) ]

9360 = 6 [ 2a - 440 ]

1560 = 2a - 440

2a = 2000

a = 1000

nth term in AP is given by:

a(n) = a + (n - 1)d

Last term = 1000 - 40(12 - 1)

=1000 - 440 = 560

Therefore first installment is 1000 and last one is 560.

Answer 2

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HERE IS UR ANSWER

$_____________________________$

money borrowed = 8000

interest=1360

total money=9360

sum of nth term

$sn = \frac{n}{2} (2a + (n - 1)d)$

$9360 = 2a + 11(40) \\ 2a = 2000 \\ a = 1000$

nth term

$an = a + (n - 1)d$

$an = 560$