Question in the attachment, Answer correctly, don't be greedy for points
Class :- 7 , school :- DAV , book :- mathematicas, worksheet 2 question no. 18
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Answers
Answer:
Let present age of seema = x yrs sudesh = = 2x yrs
4(x-6) = 2x+4
4x 24 = 2x +4
4x - 2x=4+24
2x = 28
x=14
present age of seema-14 yrs
present age of sudesh= 28 yrs 3 yrs ago age of seema = 11 yrs
3 yrs ago age of sudesh -25 yrs
seema was 11 yrs old and sudesh was 25 yrs old 3 yrs ago.
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Then I DELETED!!
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Answer:
Question :-
Sudesh is the twice as old as Seema. If 6 years is subtracted from Seema's age and four years are added to Sudesh's age, Sudesh will be four times Seema's age. How old were they 3 years ago?
Solutions :-
Let Seema's age be = x
Sudesh's age be = y
= y = 2x = 4 (x- b) = (y + 4)
= 4(x - b) = 2 (2x + 4)
= 4x - 2x = 2x + 4
= 2x = 28
- Seema's current age = 14 ,
- Sudesh's current age = 2 x 14 = 28 years
- Three years ago their ages, = 11, 25 respectively
- So, three years ago their ages were 11 and 25 respectively.