Math, asked by kalpnajha1986kp, 16 days ago

Question in the attachment, Answer correctly, don't be greedy for points

Class :- 7 , school :- DAV , book :- mathematicas, worksheet 2 question no. 18
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Correct answer only !!!​

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Answers

Answered by Anonymous
80

Answer:

Let present age of seema = x yrs sudesh = = 2x yrs

4(x-6) = 2x+4

4x 24 = 2x +4

4x - 2x=4+24

2x = 28

x=14

present age of seema-14 yrs

present age of sudesh= 28 yrs 3 yrs ago age of seema = 11 yrs

3 yrs ago age of sudesh -25 yrs

seema was 11 yrs old and sudesh was 25 yrs old 3 yrs ago.

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Then I DELETED!!

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Answered by Ayushsf2hindustan
5

Answer:

Question :-

Sudesh is the twice as old as Seema. If 6 years is subtracted from Seema's age and four years are added to Sudesh's age, Sudesh will be four times Seema's age. How old were they 3 years ago?

Solutions :-

Let Seema's age be = x

Sudesh's age be = y

= y = 2x = 4 (x- b) = (y + 4)

= 4(x - b) = 2 (2x + 4)

= 4x - 2x = 2x + 4

= 2x = 28

 = x =  \frac{28}{2}

  • Seema's current age = 14 ,
  • Sudesh's current age = 2 x 14 = 28 years

  • Three years ago their ages, = 11, 25 respectively

  • So, three years ago their ages were 11 and 25 respectively.

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