Question

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Answer 1

Answer:

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Explanation:

Hint: To solve this question, we should have prior knowledge about the calculation of number of moles. Number of moles is defined as the ratio of given mass to the molar mass.

Complete Solution :

(i) The chemical reaction involved in this question is mentioned below:

2Ca(NO3)2→2CaO+4NO2↑+O2↑

From the given reaction, we can observe that 2 moles of Ca(NO3)2 produces 4 moles of NO2 . So, one mole of Ca(NO3)2 will produce 42 mole of NO2= 2 moles of NO2 is produced.

(ii) Molar mass of Ca(NO3)2 = 164 gm

In this equation 2 moles of Ca(NO3)2 is produced, molar mass of 2 moles of Ca(NO3)2 is =2×164g .

2×164g of Ca(NO3)2 produces 22.4 L of O2

1g of Ca(NO3)2produces =22.42×164L

65.6 g of Ca(NO3)2produce =22.42×164×65610=4.48L of oxygen is produced.

(iii) 328 g of Ca(NO3)2 produce 112g of CaO

1 g of Ca(NO3)2produce 1122×164g of CaO

65.6 g of Ca(NO3)2 will produce =112328×65610=22.4g

(iv)gaseous molecules are produced in the reaction = 4 moles of NO2, and 1 mole of O2 = 5 moles

Mass of Ca(NO3)2 required will be the mass of 2 moles = 2×164=328g

(v) 4×22.4L of NO2 produce by 328 g of Ca(NO3)2

1L of NO2 will produce =3284×22.4

44.8L of NO2 will produce 3284×22.4×44.8=164g of Ca(NO3)2