Question

Question in the attachment dont spamm,give anseer with explanation.
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Answer 1

$\huge\bf{Answer:-}$

Option (B) is correct .i.e. the car has come to a stop and has zero velocity.

Further Explanation:-

According to the theory of graphs, ‘the straight line parallel to x axis’ means the quantity given on y axis is not changing or is constant with respect to the change in the quantity on x axis. This is why because the slope of that particular straight line is zero.

Concept:

Mathematically, the slope is defined as the tangent (trigonometry) of the angle made by the segment with the x axis or it is also defined as the ratio of change in the quantity on y-axis to change in the quantity on x-axis.

$\boxed{\text{slope}=\tan(\theta)}$

Here,$\thetaθ$ is the angle made by the segment of graph with x-axis

The slope can also be expressed as:

$\boxed{\text{slope}=\dfrac{\text{change in quantity given on y-axis}}{\text{change in quantity given on x-axis}}}$

 

Here, the quantity given on y axis is car’s position and that given on x axis is time taken by the car to travel.

The slope of position-time graph gives velocity.  So, by the definition of slope, we have  

$Velocity=change\:in \:position/change\: in \:time$

Here, as shown in the graph, the two ends of the segment B have same values of position on y axis. So, change in position will be zero.

Substitute 00 for $\text{change in position}$

$\text{Velocity}=0\text{ m/s}$

This shows that the speed of the car in the segment B of t