Question

question in the attachment
math class 7​

Answer 1

Answer:

Questions:-

a) Gardening shears bought for rs 250 and sold for rs 325

$profit\% = ( \frac{profit}{cp} \times 100)\% \\ = > p\% = \frac{325 - 250}{250} \\ p\% = > \frac{75}{250} \times 100 = 3 \times 10 = 30\%$

So, There is a profit of 30 %

b) A refrigerator bought rs 12,000 and sold at rs 13,500

$profit\% = ( \frac{profit}{cp} \times 100) \\ = > p\% = (\frac{13500 - 12000}{12000} \times 100)\% \\ = > p\% = \frac{1500}{12000} \times 100 \\ = > p\% = ( \frac{15}{120} \times 100) = > \frac{5}{4} \times 10 \\ = > \frac{50}{4} \ = \frac{25}{2} = 12\frac{1}{2}$

c) A cupboard bought for rs 2500 and sold for rs 3000

$p\% = (\frac{p}{cp} \times 100)\% \\ = > p\% = \frac{500}{3000} \times 100 \\ = > p\% = \frac{5}{30} \times 100 = \frac{5}{3} \times 10 \\ = > \frac{50}{3} = 16\frac{2}{3}$

d) A skirt bought for rs 250 and sold for 150 rs

$loss\% = (\frac{loss}{cp} \times 100)\% \\ = > loss\% = \frac{100}{250} \times 100 \\ = > loss\% = \frac{10}{25} \times 100 \\ = > loss\% = 10 \times 4 = 40\%$

There is a loss of 40%

Answer 2

Step-by-step explanation:

Answer:- (a) cost price (cp)=250

sold price (sp)=325

loss=sp-cp=325-250=75. (sp>cp)

now % of loss= amount of lost÷cp×100

=75÷250×100=30%