Question. In the following figure, the diagonal AC and BD of a rhombus ABCD intersect at O. P and Q are mid-points of OA and OB respectively. If AC = 8 cm and BD = 6 cm then the length of PQ is
(a) 3 cm
(b) 4 cm
(c) 5 cm
(d) 2.5 cm
Attachments:
Answers
Answered by
0
Answer:
5 is the answer .........
Answered by
0
Step-by-step explanation:
AC = 8cm so 1/2 x AC = AO
1/2 x 8 = 4
BD = 6 cm so 1/2 x BD = BO
1/2 x 6 = 3
In ΔAOB , AB^2 = AO^2 + BO^2
= 4^2 + 3^2
= 16 + 9
AB ^ 2 = 25
AB = 5
By midpoint theorem,
PQ is parallel to AB and PQ is half of AB
Therefore PQ = 2.5
Similar questions