Math, asked by Yeshwanth1234, 9 months ago

Question In the given figure the wedge is acted on by a constant horizontal force F. The wedge is moving on a smooth horizontal surface. A ball of mass ‘m’ is at rest relative to the wedge. The ratio of forces exerted on ‘m’ by the wedge when F is acting and F is withdrawn assuming no friction between the ways and the ball, is equal to

Answers

Answered by Yeshwanth1245
1

the answer is sec^2\theta

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Answered by manjulap1741
1

Answer:

there is no figure or this is the question

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