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Answer:
Given
MN = MP
MR _|_ NP ( /_MRN = /_MRP = 90°)
To Prove :- ∆NMR congruent to ∆PMR
Proof :-
In ∆NMR & ∆PMR
MN = MP ( Given)
/_MRN = /_MRP(90°)
MR = MR ( common)
∆NMR congruent to ∆PMR by SSA
Answered by
0
Answer:
Given
MN = MP
MR _|_ NP ( /_MRN = /_MRP = 90°)
To Prove :- ∆NMR congruent to ∆PMR
Proof :-
In ∆NMR & ∆PMR
MN = MP ( Given)
/_MRN = /_MRP(90°)
MR = MR ( common)
∆NMR congruent to ∆PMR by SSA
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