Math, asked by ranjodhsinghhothi12, 5 months ago

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Answered by Himanidaga
2

Answer:

Given

MN = MP

MR _|_ NP ( /_MRN = /_MRP = 90°)

To Prove :- ∆NMR congruent to ∆PMR

Proof :-

In ∆NMR & ∆PMR

MN = MP ( Given)

/_MRN = /_MRP(90°)

MR = MR ( common)

∆NMR congruent to ∆PMR by SSA

Answered by MissAlison
0

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Answer:

Given

MN = MP

MR _|_ NP ( /_MRN = /_MRP = 90°)

To Prove :- ∆NMR congruent to ∆PMR

Proof :-

In ∆NMR & ∆PMR

MN = MP ( Given)

/_MRN = /_MRP(90°)

MR = MR ( common)

∆NMR congruent to ∆PMR by SSA

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