Question

Question:-in triangle abc right angled at b,if tan A=3/2 then the value of cos A is?
(a)3/√13
(b)2√13
(c)2/3
(d)√13/2​

Answer 1

Answer:

tan A = 3/2

then cosA = 2/√13

option b is correct

Answer 2

Given,

Triangle ABC is right angled triangle. Angle B is right angle.

$\[\tan A = \frac{3}{2}\]$

Solution,

Calculate the value of $\[\cos A\]$

$\[\cos A = \frac{2}{{\sqrt {{2^2} + {3^2}} }}\]$

$\[ \Rightarrow \cos A = \frac{2}{{\sqrt {4 + 9} }}\]$

$\[ \Rightarrow \cos A = \frac{2}{{\sqrt {13} }}\]$

Hence the value of $\[\cos A\]$ is $\[\frac{2}{{\sqrt {13} }}\]$

The correct option is (b), i.e. $\[\frac{2}{{\sqrt {13} }}\]$