Math, asked by adi6160, 3 months ago

Question is 5 raised to the power of -4x multiplied by 5 raised to the power of x square+ 4 is equal to = 1.
Then find the value of x.
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Answers

Answered by mathdude500
3

Answer:

\large{\boxed{\boxed{\sf{Question}}}}

\bf \:Solve  \: for \:  x :-  {5}^{ - 4x}  \times  {5}^{ {x}^{2}  + 4}  = 1

\huge{\boxed{\rm{Answer}}}

\large{\boxed{\boxed{\sf{Given \: that}}}}

\bf \: {5}^{ - 4x}  \times  {5}^{ {x}^{2}  + 4}  = 1

\large{\boxed{\boxed{\sf{To \: find}}}}

  • Value of x

Identity used :-

\bf \: {a}^{m}  \times  {a}^{n}  =  {a}^{m + n}

\bf \: {a}^{0}  = 1

\bf \: {a}^{m}  =  {a}^{n} ⟹ \: m = n

\large{\boxed{\boxed{\sf{Solution}}}}

\bf \: {5}^{ - 4x}  \times  {5}^{ {x}^{2}  + 4}  = 1

\bf\implies \:  {5}^{  - 4x  \: +  \: {x}^{2}  + 4}  =  {5}^{0}

\bf\implies \: {x}^{2}  - 4x + 4 = 0

\bf\implies \: {x}^{2}  - 2x - 2x + 4 = 0

\bf\implies \:x(x - 2) - 2(x - 2) = 0

\bf\implies \:(x - 2)(x - 2) = 0

\bf\implies \:x = 2

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