question is attached below
Answers
1. 2xy/(x+y)=3/2 xy/(2x-y)=-3/10
4xy=3x+3y 10xy=-6x+3y............(2)
y(4x-3)=3x put (1) into (2), 10x[3x/(4x-3)]=-6x+3[3x/(4x-3)]
y=3x/(4x-3)...........(1) 30x^2/(4x-3)=-6x+9x/(4x-3)
10x/(4x-3)=-2+3/(4x-3)
10x=-2(4x-3)+3
y=3x/(4x-3) 10x=-8x+6+3
y=3(1/2)/[4(1/2)-3] 18x=9
=3/2/(2-3) x=1/2
=3/-2
=-3/2 so x=1/2, y=-3/2