Question

Question is attached !

Organic Chemistry !!! ​

Answer 1

answer

option (a) is correct

explaination

the reaction involved would be like:

$\boxed{\red{\tt R-Ch^2OH ---> R-COOH+Mno^2 }}$

according to this equation the value of p would be assigned as R-COOH which is option (a).

Answer 2

Explanation:

Aldehydes are prepared by the oxidation of alcohol with KMnO4/KOH.

It means,

When R-CH2-OH reacts with KMnO4 and OH- then it gets oxidised to Aldehyde.

• R-CH2-OH + [O] → R-CHO + H2O

Note :-

• Aldehyde formed in the above reaction readily oxidised to form Carboxylic acid.

R-CHO reacts with H+ to gets oxidised to Carboxylic acid.

Further reaction :-

• R-CHO + [O] → R-COOH

Note :-

• Aldehyde are readily oxidised to corresponding Carboxylic acids with common oxidising agent KMnO4 in neutral, acidic or alkaline medium.

Hence,

Here, P (major product) is R-COOH

Therefore,

Option A is correct.

Additional information :-

Physical state :-

• At room temperature, lower alcohols are colourless liquids with distinct smell and burning taste.
• The higher member are colourless, odourless, waxy solid.

Boiling point :-

• The boiling point of alcohol and phenols increase with increase in number of C-atoms.

Reason -

Due to increase in van der waals' force.

Solubility :-

• The solubility of alcohols and phenols in water is due to their ability to form H-bonds with water molecules