Question

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Answer 1

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Answer 2

Answer:

Prove by congruency of triangles.

Note that you must be frequent with tangent properties.

Step-by-step explanation:

In Δ APQ and Δ PQB ,

PQ = PQ [ Common ]

∠ PAQ = ∠ PBQ [ Same segment ]

∠ APQ = ∠ BPQ [ 90° each ]

Δ APQ ≅ Δ BPQ [ A.A.S ]

QA = QB [ c.p.c.t ]