question is chapeter of sets. in a commite is 50people speak french ,20people speak spanish,10people speak both spanish and french how many speak at list one of two tounguages?
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Answer: all 80
Step-by-step explanation:total no, of people in commitee speak french ,spanish and 10 speak both so the people that speak at least will be 80 the sum of 50 ,20 and 10.as it says that they should speak at least one language
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Step-by-step explanation:
Answer:
LET
F the set of people in the committee who speak FRANCEH.
S the set of people in the committee who speak SPANISH.
n(F)=50, n(S)=20, n(SuF)=10
therefore,
n(SuF)=n(F)+n(S)-n(SuF)
=50+20-10
=70-10
=60
therefore,60 people speak at least one of these two languages...
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