Math, asked by kiran2096, 11 months ago

question is chapeter of sets. in a commite is 50people speak french ,20people speak spanish,10people speak both spanish and french how many speak at list one of two tounguages?​

Answers

Answered by bhavy478
1

Answer: all 80

Step-by-step explanation:total no, of people in commitee speak french ,spanish  and  10 speak both so the people that speak at least will be 80 the sum of 50 ,20 and 10.as it says that they should speak at least one language

Answered by nilutpalgogoi314
0

Step-by-step explanation:

Answer:

LET

F the set of people in the committee who speak FRANCEH.

S the set of people in the committee who speak SPANISH.

n(F)=50, n(S)=20, n(SuF)=10

therefore,

n(SuF)=n(F)+n(S)-n(SuF)

=50+20-10

=70-10

=60

therefore,60 people speak at least one of these two languages...

☝️i hope its helpful to you...☝️

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