Question

QUESTION is:

Find the amount if Rs.40000 are invested for 2 years at 2 1/2 compound interest.

ANSWER this question is: 42025
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Answer 1

Answer:

Answer is 42025 at 2 years at 2 1/2 compound interest.

Answer 2

Step-by-step explanation:

Principle =  Rs.40000

Time =   2 years

Time =   2 yearsRate = 2 1/2% = 2.50%

Time =   2 yearsRate = 2 1/2% = 2.50%Formula:

Time =   2 yearsRate = 2 1/2% = 2.50%Formula:AA =P(1+R/100P(1+R/100 )^{n})n

Time =   2 yearsRate = 2 1/2% = 2.50%Formula:AA =P(1+R/100P(1+R/100 )^{n})nA = amount

Time =   2 yearsRate = 2 1/2% = 2.50%Formula:AA =P(1+R/100P(1+R/100 )^{n})nA = amountP = principle

Time =   2 yearsRate = 2 1/2% = 2.50%Formula:AA =P(1+R/100P(1+R/100 )^{n})nA = amountP = principleR = rate of interest

Time =   2 yearsRate = 2 1/2% = 2.50%Formula:AA =P(1+R/100P(1+R/100 )^{n})nA = amountP = principleR = rate of interestn = times of years

Time =   2 yearsRate = 2 1/2% = 2.50%Formula:AA =P(1+R/100P(1+R/100 )^{n})nA = amountP = principleR = rate of interestn = times of yearsCalulation:

Time =   2 yearsRate = 2 1/2% = 2.50%Formula:AA =P(1+R/100P(1+R/100 )^{n})nA = amountP = principleR = rate of interestn = times of yearsCalulation:A= 40000(1+2.50/100)^240000(1+2.50/100)2

Time =   2 yearsRate = 2 1/2% = 2.50%Formula:AA =P(1+R/100P(1+R/100 )^{n})nA = amountP = principleR = rate of interestn = times of yearsCalulation:A= 40000(1+2.50/100)^240000(1+2.50/100)2A = 40000(1+0.025)^240000(1+0.025)2

Time =   2 yearsRate = 2 1/2% = 2.50%Formula:AA =P(1+R/100P(1+R/100 )^{n})nA = amountP = principleR = rate of interestn = times of yearsCalulation:A= 40000(1+2.50/100)^240000(1+2.50/100)2A = 40000(1+0.025)^240000(1+0.025)2A = 40000(1.025)^240000(1.025)2

Time =   2 yearsRate = 2 1/2% = 2.50%Formula:AA =P(1+R/100P(1+R/100 )^{n})nA = amountP = principleR = rate of interestn = times of yearsCalulation:A= 40000(1+2.50/100)^240000(1+2.50/100)2A = 40000(1+0.025)^240000(1+0.025)2A = 40000(1.025)^240000(1.025)2A = 40000(1.050625)

Time =   2 yearsRate = 2 1/2% = 2.50%Formula:AA =P(1+R/100P(1+R/100 )^{n})nA = amountP = principleR = rate of interestn = times of yearsCalulation:A= 40000(1+2.50/100)^240000(1+2.50/100)2A = 40000(1+0.025)^240000(1+0.025)2A = 40000(1.025)^240000(1.025)2A = 40000(1.050625)A = 42025

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