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Answer 1

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$(i) \\ \frac{(3 {x}^{2} - 2x) }{x} \\ = \frac{x(3x - 2)}{x} \\ = 3x - 2 \\ \\ \bold\green{\boxed {Answer:\:3x - 2}} \\ \\ \\ (ii) \\ \frac{(5 {a}^{3} b - 7a {b}^{3}) }{ab} \\ = \frac{ab( 5 {a}^{2} - 7 {b}^{2} )}{ab} \\ = 5 {a}^{2} - 7 {b}^{2} \\ \\ \bold\green{\boxed {Answer:\:5 {a}^{2} - 7 {b}^{2}}} \\ \\ \\(iii) \\ \frac{(25 {x}^{5} - 15 {x}^{4} )}{5 {x}^{3} } \\ = \frac{5 {x}^{3} (5 {x}^{2} - 3x) }{5 {x}^{3} } \\ = 5 {x}^{2} - 3x \\ \\ \bold\green{\boxed {Answer:\:5 {x}^{2} - 3x }} \\ \\ \\ (iv) \\ \frac{4 {l}^{2} - 6 {l}^{4} + 8 {l}^{3} }{2 {l}^{2} } \\ = \frac{2 {l}^{2}(2 - 3 {l}^{2} + 4l) }{2 {l}^{2} } \\ = 2 - {l}^{2} + 4l \\ \\ \bold\green{\boxed {Answer:\:2 - {l}^{2} + 4l}} \\ \\ \\ (v) \\ \frac{15( {a}^{3} {b}^{2} {c}^{2} - {a}^{2} {b}^{3} {c}^{2} + {a}^{2} {b}^{2} {c}^{3} )}{3abc} \\ = \frac{15abc( {a}^{2}bc - a {b}^{2} c + ab {c}^{2} )}{3abc} \\ = 5 {a}^{2}bc - 5a {b}^{2} c + 5ab {c}^{2} \\ \\ \bold\green{\boxed {Answer:\:5 {a}^{2}bc - 5a {b}^{2} c + 5ab {c}^{2} }} \\ \\ \\ (vi) \\ \frac{(3 {p}^{3} - 9 {p}^{2}q - 6p {q}^{2} ) }{3p} \\ = \frac{3p( {p}^{2} - 3 pq - 2 {q}^{2} ) }{3p} \\ = {p}^{2} - 3pq - 2 {q}^{2} \\ \\ \bold\green{\boxed {Answer:\:{p}^{2} - 3pq - 2 {q}^{2}}} \\ \\ \\ (vii) \\ \frac{ (\frac{2}{3} {a}^{2} {b}^{2} {c}^{2} + \frac{4}{3} a {b}^{2} {c}^{2} ) }{ \frac{1}{2}abc } \\ = \frac{\frac{1}{2}abc( \frac{4}{3 } abc + \frac{8}{3}bc) }{ \frac{1}{2}abc } \\ = \frac{4}{3}abc + \frac{8}{3} bc \\ \\ \bold\green{\boxed {Answer:\:\frac{4}{3}abc + \frac{8}{3} bc \: }}$

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Answer 2

Answer:

Here is the correct answer.