Math, asked by 11manjuapril, 10 hours ago

question is in aat@chment
q4..

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Answered by tennetiraj86
2

Step-by-step explanation:

Given :-

Sin 750° Cos 300° + Cos 1470° Sin (-1020°)

To find:-

Find the value of the given expression?

Solution:-

Given that :-

Sin 750° Cos 300° + Cos 1470° Sin (-1020°)

Sin 750° can be written as

Sin 750° = Sin (720°+30°)

=> Sin 750° = Sin (2×360°+30°)

=> Sin 750° = Sin 30°

Since Sin (360°+A) = Sin A

and

Cos 300° = Cos (270°+30°)

=> Cos 300° = Sin 30°

Since Cos (270°+A) = Sin A

Cos 1470° = Cos (1440°+30°)

=> Cos 1470° = Cos (4×360°+30°)

=> Cos 1470° = Cos 30°

Since Cos (360°+A) = Cos A

and

Sin (-1020°) = - Sin 1020°

Since Sin (-A) = - Sin A

=> Sin 1020° = -[Sin (1080°-60°)]

=> Sin 1020° = -[Sin (3×360°-60°)]

=> Sin 1020° = -[- Sin 60°]

Since Sin (360°-A) = - Sin A

=> Sin (-1020°) = Sin 60°

Now given expression becomes

=> Sin 750° Cos 300° + Cos 1470° Sin (-1020°)

=> Sin 30° .Sin 30° + Cos 30°. Sin 60°

=> (1/2).(1/2) + (√3/2).(√3/2)

=> (1/4)+(√3×√3)/4

=> (1/4)+(3/4)

=> (1+3)/4

=> 4/4

=> 1

or

Sin 30° .Sin 30° + Cos 30°. Sin 60°

=> Sin² 30° + Cos 30° Sin (90°-30°)

=> Sin² 30° + Cos30° . Cos 30°

Since Sin (90°-A) = Cos A

=> Sin² 30° + Cos² 30°

We know that

Sin² A + Cos² A = 1

=> Sin² 30° + Cos² 30°

=>1

Answer:-

The value of the expression :

Sin 750° Cos 300° + Cos 1470° Sin (-1020°) is 1

Used formulae:-

  • Sin (360°+A) = Sin A
  • Cos (360°+A) = Cos A
  • Sin (-A) = - Sin A
  • Cos (270°+A) = Sin A
  • Sin (360°-A) = - Sin A
  • Sin 30° = 1/2
  • Cos 60° = √3/2
  • Cos 30° = √3/2
  • Sin (90°-A) = Cos A
  • Sin² A + Cos² A = 1
Answered by djswain9
1

Step-by-step explanation:

please check the values may be the values are wrong . if any query then ask

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