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Answer:
(i) 135 and 225
Since 225 > 135 , we apply the division lemma to 225 and 135 to obtain
225=135×1+90
Since remainder 90≠0 , we apply the division lemma to 135 and 90 to obtain
135=90×1+45
We consider the new divisor 90 and new remainder 45 , and apply the division lemma to obtain
90=2×45+0
Since the remainder is zero , the process stops.
Since the divisor at this stage is 45,
Therefore the HCF of 135 and 225 is 45.
Answer:
(i) 135 and 225
Since 225 > 135 , we apply the division lemma to 225 and 135 to obtain
225=135×1+90
Since remainder 90≠0 , we apply the division lemma to 135 and 90 to obtain
135=90×1+45
We consider the new divisor 90 and new remainder 45 , and apply the division lemma to obtain
90=2×45+0
Since the remainder is zero , the process stops.
Since the divisor at this stage is 45,
Therefore the HCF of 135 and 225 is 45.
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