Math, asked by Anonymous, 1 month ago

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Answered by hareem23
2

Answer:

(i) 135 and 225

Since 225 > 135 , we apply the division lemma to 225 and 135 to obtain

225=135×1+90

Since remainder 90≠0 , we apply the division lemma to 135 and 90 to obtain

135=90×1+45

We consider the new divisor 90 and new remainder 45 , and apply the division lemma to obtain

90=2×45+0

Since the remainder is zero , the process stops.

Since the divisor at this stage is 45,

Therefore the HCF of 135 and 225 is 45.

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Answered by Heer56
1

Answer:

 \\

(i) 135 and 225

Since 225 > 135 , we apply the division lemma to 225 and 135 to obtain

225=135×1+90

Since remainder 90≠0 , we apply the division lemma to 135 and 90 to obtain

135=90×1+45

We consider the new divisor 90 and new remainder 45 , and apply the division lemma to obtain

90=2×45+0

Since the remainder is zero , the process stops.

Since the divisor at this stage is 45,

Therefore the HCF of 135 and 225 is 45.

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