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Yes, it's possible.
Ans: length=20m
Breadth =20m
Ans: length=20m
Breadth =20m
Sudhirking:
No
Answered by
2
Hey there!
Perimeter = 2(l+b) = 80m
l+b = 40m
l = 40-b
Area = l×b = 400m²
(40-b)×b = 400
40b-b²-400 = 0
-b²+40b-400 =0
b²-40b+400 = 0
b²-20b-20b+400 =0
b(b-20) -20(b-20) = 0
b-20 = 0 b-20 =0
b = 20 b= 20.
Therefore breadth = 20m
l+b = 40m
l+20 = 40
l = 20m
Hence it is possible to design a recatangle with Perimeter 80m and area 400m².
Length = 20m and breadth = 20m
:)
Perimeter = 2(l+b) = 80m
l+b = 40m
l = 40-b
Area = l×b = 400m²
(40-b)×b = 400
40b-b²-400 = 0
-b²+40b-400 =0
b²-40b+400 = 0
b²-20b-20b+400 =0
b(b-20) -20(b-20) = 0
b-20 = 0 b-20 =0
b = 20 b= 20.
Therefore breadth = 20m
l+b = 40m
l+20 = 40
l = 20m
Hence it is possible to design a recatangle with Perimeter 80m and area 400m².
Length = 20m and breadth = 20m
:)
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