Question

Question is in image

Answer 1

Answer:

NH4NO3 can be written as (NH4)+ + (NO3)-. From here x1 = -3. Hence we find two different oxidation numbers of N in NH4NO3. They are -3 and +5.

Answer 2

The given molecule is made up of the combination of two ion which are ammonium ion 

 and nitrite ion 

. In this nitrite ion is the counter ion.

Now we have to determine the oxidation number of N in both the ions.

The oxidation number of N in 

:

Let the oxidation number of 'N' be 'x'.

The oxidation number of N in 

:

Let the oxidation number of 'N' be 'x'.

Hence, the oxidation number of N in are, (-3) and (+3).

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