Question

question is in the attachment​

Answer 1

Answer:

In ΔAPC & ΔAQB

= AC = AB                { Given }

= ∠A = ∠A                { Common }

= AP = AQ                { Given }

∴ By SAS, ΔAPC ≅ ΔAQB

∴ PC = QB           { CPCT }

                                                                                  HENCE PROVED.

PLZ MARK AS BRAINLEST.

OR GIVE ! 10 THANK

Answer 2

Answer:

Triangle APC and Triangle AOB

AC=AB (Given)

Angle A=Angle A (Common)

Ap= AQ (Given)

Triangle APC = Triangle AQB (S.A.S.)

:.PC =QB