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Answer 1

Answer :-

Percentage composition of Potassium Hydrogen Sulphate [KHSO₄] is :-

→ Potassium (K) = 28.68 %

→ Hydrogen (H) = 0.73 %

→ Sulphur (S) = 23.53 %

→ Oxygen (O) = 47.06 %

Explanation :-

In order to solve this problem, we should firstly know :-

• Atomic mass of Potassium (K) = 39 u

• Atomic mass of Hydrogen (H) = 1 u

• Atomic mass of Sulphur (S) = 32 u

• Atomic mass of Oxygen (O) = 16 u

So, molecular mass of KHSO₄ :-

= 39 + 1 + 32 + 16 × 4

= 72 + 64

= 136 u

________________________________

Percentage of Potassium :-

= 39/136 × 100

= 3900/136

= 28.68 %

Percentage of Hydrogen :-

= 1/136 × 100

= 100/136

= 0.73 %

Percentage of Sulphur :-

= 32/136 × 100

= 3200/136

= 23.53 %

Percentage of Oxygen :-

= 64/136 × 100

= 6400/136

= 47.06 %

Answer 2

Answer:

Required Answer :-

Explanation:

he elements in KHSO4 are :-

Potassium

Hydrogen

Sulphur

Oxygen

We know that

Potassium atomic mass = 39

Hydrogen atomic mass = 1

Sulphur atomic mass = 32

Oxygen atomic mass = 16

Now

KHSO4

By putting all values

(39) + (1) + (32) + (16 × 4)

40 + 32 + 64

72 + 64

136

Now calculating all of them

Potassium = Atomic mass × 100/Molecular mass

Potassium = 39 × 100/136

Potassium = 3900/136

Potassium = 28.7 %

For Hydrogen

Hydrogen = Atomic mass × 100/Molecular mass

Hydrogen = 1 × 100/136

Hydrogen = 100/136

Hydrogen = 0.7 %

For Sulphur

Sulphur =  Atomic mass × 100/Molecular mass

Sulphur = 32 × 100/136

Sulphur = 3200/136

Sulphur = 23.5%

For Oxygen

Oxygen =  Atomic mass × 100/Molecular mass

Oxygen = 64 × 100/136

Oxygen = 6400/136

Oxygen = 47 %