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Answered by SƬᏗᏒᏇᏗƦƦᎥᎧƦ
114

Information provided with us :

  • A.P. is 4.2 , 4.7 , 5.2 , 5.7
  • last term (l) of that A.P. is 8.7

What we have to calculate :

  • No of terms of that A.P. (n) ?

Using Formula :

We know that nth term of an A.P. is calculated by,

  • \boxed{\red{\bf{t_{n  } = a+ (n - 1)d}}}

Here,

  • a is first term of the A.P.
  • tn or l is the last term
  • d is common difference
  • n is number of terms

Performing Calculations :

We have :

  • Last term or t_n is 8.7
  • first term (a) is 4.2

Finding out common difference :-

Here we would be calculating the common difference (d) by subtracting the first term (a) with the second term of the A.P and so on~

 \implies \:   \sf{Common \: difference (d) \: = 4.7 - 4.2}

 \implies \:       \large{\pink{\boxed{\bf{Common \: difference (d) = 0.5}}}}

\therefore  \: \bf{\underline{Common \: difference \: (d) \: is \: 0.5 \: respectively}}

Putting the values in the formula :-

Here we would be calculating the number of terms of that A.P. (Arithmetic progression) by substituting all the values~

 : \longmapsto  \sf{8.7 = 4.2 + (n - 1) 0.5}

 : \longmapsto 8.7 = 4.2 + (n - 1) × 0.5

 : \longmapsto 8.7 - 4.2 = (n - 1) × 0.5

 :  \longmapsto \:  \sf{(n - 1) \:  =  \:  \dfrac{8.7 - 4.2}{0.5}}

 :  \longmapsto \:  \sf{(n - 1) \:  =  \:  \dfrac{4.5}{0.5}}

:  \longmapsto \:  \sf{(n - 1) \:  =  \:  \dfrac{45 \times 10}{05 \times 10}}

:  \longmapsto \:  \sf{(n - 1) \:  =  \:  \dfrac{450}{50}}

:  \longmapsto \:  \sf{(n - 1) \:  =  \:   \cancel\dfrac{450}{50}}

 :  \longmapsto \:  \sf{(n - 1) \:  =  \:  \dfrac{45}{5}}

:  \longmapsto \:  \sf{(n - 1) \:  =  \:   \cancel\dfrac{45}{5}}

 :  \longmapsto \:  \sf{(n - 1) \:  =  \:   9}

 : \longmapsto n - 1 = 9

 : \longmapsto n = 9 + 1

 :  \longmapsto \:    \red{\boxed{\bf{n  \:  =  \:10}}}

 \underline{\bf{Henceforth,  \: 10th \: term \: of \: the \: A.P. \: is \: 8.7}}

Additional Information :

  • Arithmetic progression (A.P.) is a sequence in which each term can be found by adding a certain quantity to its preceding term
  • Difference between two consecutive terms is called common difference
  • Progression means it's a type of sequence in which each term is related to its predecessor and successor.

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Answered by vandanathakur509
1

Answer:

you should + 5 in each

Step-by-step explanation:

5.7, 6.2,6.7, 7.2, 7.7, 8.2

Please mark me as brainlist

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